If 4 circles of equal radius are drawn with vertices of a square as the centre , the side of the square being 7 cm, find the area of the circles outside the square?

• 4*(3/4*pi*3.5*3.5)==115.5 sq cm
  this answer is true only if we assume that one circle touches 2 other circles at only one point.....
• 11 years agoHelpfull: Yes(2) No(0)
• The area will be 3*3.14*3.5*3.5=115.395 cm2
  because each vertice of the square is the center of a circle
  (1/4) part of the total area of each circle inside of the square.
  (3/4) part of the total area of each circle outside of the square.
  Thus total area outside of the square is 3*(3/4)*3.14*3.5*3.5=115.395 cm2
  here 3.5 is the radius of each circle.
  
  
  
  
• 10 years agoHelpfull: Yes(0) No(0)