Bird A starts flying from P to Q at 9.00 A.M. and bird B starts flying from Q to P at 10.00 A.M. B is 50% faster than A. What is the time at which they meet if P and Q are 300kms apart and A’s speed is 50kmph.

a) 12 noon b) 12.30pm c) 11.30am d) 11.00am

• it should be 12 noon
  
• 10 years agoHelpfull: Yes(6) No(0)
• Distance traveled by A in one hour+Distance traveled by A after B starts flying+Distance traveled by B=300
  50*1+50*t+75*t=300
  t=2 hrs
  So, 12 noon
• 10 years agoHelpfull: Yes(3) No(0)
• 11:00am
  50[y+1]+3/2*50y=300
  y=2.
• 11 years agoHelpfull: Yes(1) No(6)
• they meet at 12 noon
  
• 10 years agoHelpfull: Yes(1) No(0)
• d) 11:00 am
  
• 10 years agoHelpfull: Yes(0) No(0)
• a) 12 noon
• 8 years agoHelpfull: Yes(0) No(0)