The length of a rectangle is 1cm longer than its width.
If the diagonal of the rectangle is 4cm, what are the dimensions of the rectangle?

• let length=l,width=w;
  according to the problem l=w+1;
  diagonal^2=l^2+w^2;
  16=(w+1)^2+w^2;
  16=w^2+2w+1+w^2;
  16=2w^2+2w+1;
  2w^2+2w-15=0
  w=2.28;l=3.28
• 10 years agoHelpfull: Yes(0) No(0)