A,B,C, can do a work in 8,14,16 days respectively. A does the work for 2 days. B continues from it and finishes till 25% of the remaining work. C finishes the remaining work. How many days would have taken to complete the work?

• A works for 2 days. since he needs 8 days for completing the whole work he has completed 25% work in 2 days
  
  So remaining work = 75%.
  
  B works till 25% is remaining, i.e. B completes 50 % work which will take him 0.5 * 14 = 7 days.
  
  C completes remaining 25% work which takes him 0.25 * 16 = 4 days.
  
  So total days for work completion = 2 + 7 + 4 = 13 days
• 11 years agoHelpfull: Yes(11) No(2)
• a=1/8*2,b=1/14*7,c=1/16*4
  =>2+7+4=13
• 9 years agoHelpfull: Yes(1) No(0)
• Remaining work after A:
  = 1 - 2(1/8)
  = (4 - 1)/4
  = 3/4
  No. of days B worked:
  1/14x = 1/2
  x = 7
  No. of days C worked:
  x(1/16) = 1/4
  x = 4
  No. of days:
  = 2 + 7 + 4
  = 13
• 10 years agoHelpfull: Yes(0) No(1)
• 13 days.....................
  
• 9 years agoHelpfull: Yes(0) No(0)