In IPL season ,sachin current batting average is 51.In finals he scores 78 runs, then is batting average will be 54.find out the total number of matches played by sachin in this season.
a,6
b,8
c,9
d,10

• Let total no. of matches = x
  then, total runs 54*x
  total runs before final = 51*(x-1)
  runs in final match
  54*x - 51*(x-1) = 78
  By solving this equation.....
  x= 9
• 9 years agoHelpfull: Yes(23) No(2)
• opp:-c
  
  54+n*3= 78
  => n=8
  so total no. of matches= n+1= 9
• 9 years agoHelpfull: Yes(7) No(1)
• let t be total score of all matches played, n be total matches played
  t/n=51------>1
  t+78/(n+1)=54-------2
  substituting t=51n in eqn2 then
  51n+78=54n+54
  solving it we get n=8....total no of matches played is 8
  
• 9 years agoHelpfull: Yes(4) No(10)
• 51(x-1)+78/x =54
  so x=9
  Total number of matches played by Sachin is 9.
• 9 years agoHelpfull: Yes(2) No(0)
• c.9
  let t is total and x is no.of matches then t/x=51 and t+78/x+1=54 by solving we get x=8 but we need x+1 including ipl so ans is 9
• 9 years agoHelpfull: Yes(2) No(0)
• 51(x-1) + 78 = 54x
  51x - 51 + 78 = 54x
  27 = 3x
  x = 9
• 9 years agoHelpfull: Yes(1) No(0)
• Let number of matches played before final is x
  and average before final is 51
  After scoring 78 in final average becomes 54
  
  so we can write it as
  
  
  (51*x +78)/(x+1) =54.
  by solving this we get 8 as value of x
  
  Hence including final total number of matches would be 8+1=9.
  
• 9 years agoHelpfull: Yes(1) No(0)
• 51X + 78 = 54 (X+1)
  
  X=8
• 9 years agoHelpfull: Yes(1) No(2)
• suppose no. of matches = x
  then total no. of runs = 51x
  given last runs =78 runs
  toal avg=54
  then (51x+78)/x+1=54
  therefore x=8
  
• 9 years agoHelpfull: Yes(1) No(9)
• answer would be 8
  
• 9 years agoHelpfull: Yes(1) No(2)
• Let the no. of matches be x
  present total scores = 51x
  after final round scores average is
  (51x+78)/(x+1) = 54
  51x+78 = 54x+54
  54x-51x = 78-54
  3x = 24
  x = 8
  total no. of matches = x+1
  = 8+1 = 9 ans.
• 8 years agoHelpfull: Yes(1) No(0)
• 51*8=408
  408+78=486
  486/9=54
  so ans is c
• 9 years agoHelpfull: Yes(0) No(0)
• let r be total run
  let n be no of match
  r/n=51
  r+78/n+1=54
  by solving both equation
  we get n=8
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
• 9 years agoHelpfull: Yes(0) No(5)
• Suppose total played matches=x
  Ans is 9
• 9 years agoHelpfull: Yes(0) No(0)
• let total played matches = x
  
  before final, no. of matches = (x-1) and
  
  for (x-1) matches, avg is 51.
  
  hence total runs for (x-1) matches = 51(x-1)
  
  Runs scored in finals = 78
  
  hence total runs in x matches = 51(x-1)+78 whose avg is 54.
  
  hence (51(x-1)+78)/x = 54
  (51x-51+78)/x = 54
  3x = 27
  x = 27/3
  x = 9
  
  Ans is (c) 9.
• 9 years agoHelpfull: Yes(0) No(0)
• (51x + 78) /x+1 =54
  x=8
  total no of matches= x+1=9
• 7 years agoHelpfull: Yes(0) No(0)