From a pack of cards Jack, Queen, King & ace are removed. Then the algebraic sum of rest of the cards is

• 4(2+3+4+5+6+7+8+9+10)=216
• 9 years agoHelpfull: Yes(8) No(0)
• 4(2+3+4+5+6+7+8+9)
• 10 years agoHelpfull: Yes(2) No(2)
• Ans = 180
  Exp = A pack of card contain four different signs of cards.
  Each sign carry sum of cards is 45(1+2+3+4+5+6+7+8+9)
  by this, 4 signs is equal to 4(45)=180
  
  $ Answered by Vignesh(India, TamilNadu) $
• 12 years agoHelpfull: Yes(0) No(14)
• cards =4 [ 1,2,3----------------------13 ]
  here the jack =11, queen = 12 king = 13& ace = 1 are removed
  then the sum = 4 [ 2.3.4.5.-----------------10]
  = 4 [ 9/2( 2+ 10)] [ using the A. P.is-- Sn = n/2( a1 + an ]
  = 4*9/2* 12= 216
  ANS:216
• 8 years agoHelpfull: Yes(0) No(0)