From a pack of cards Jack Queen King ace are removed Then the algebraic sum of rest of the cards

4(2+3+4+5+6+7+8+9)
11 years agoHelpfull: Yes(2) No(2)
Ans = 180
Exp = A pack of card contain four different signs of cards.
Each sign carry sum of cards is 45(1+2+3+4+5+6+7+8+9)
by this, 4 signs is equal to 4(45)=180

$ Answered by Vignesh(India, TamilNadu) $
13 years agoHelpfull: Yes(0) No(14)
cards =4 [ 1,2,3----------------------13 ]
here the jack =11, queen = 12 king = 13& ace = 1 are removed
then the sum = 4 [ 2.3.4.5.-----------------10]
= 4 [ 9/2( 2+ 10)] [ using the A. P.is-- Sn = n/2( a1 + an ]
= 4*9/2* 12= 216
ANS:216
9 years agoHelpfull: Yes(0) No(0)

From a pack of cards Jack, Queen, King & ace are removed. Then the algebraic sum of rest of the cards is