B is 50% faster than A. If A starts at 9 A.M. and B starts at 10 A.M. A travels at a speed of 50 km/hr. If A and B are 300 kms apart, The time when they meet when they travel in opposite direction is?

• let t be the elapsed time since A starts
  
  50 t + 1.5*50(t-1) = 300
  
  50 t +75 t = 300 + 75
  
  t = 375 / 125 = 3 hrs past the time that A starts
  so they meet at 12:00 noon
• 11 years agoHelpfull: Yes(6) No(3)
• By 10 A.M., A had been traveling for 1 hr, covering a distance of 50 Km at 50 km per hr.
  Speed of B=50+50%*50=50+25=75 km/hr
  let x=travel time (hours) it would take for A & B to meet after 10 A.M.
  (x+1) = total travel time (hours) of A
  
  distance=speed*travel time
  50(x+1)+75x=300
  50x+50+75x=300
  125x=250
  x=2 hrs
  
  The time when they meet when they travel in opposite directions is=10+2=12 noon
• 10 years agoHelpfull: Yes(5) No(1)
• A 50 km/h
  50% of A = 25 km/h
  B travels at 75km/h
  B starts at 10 am.
  A starts at 9 am
  A travels 50 km in 1 hour
  when B starts they are 300 -50 km apart.
  =250km.
  Speed together = 50+75 = 125 km/h
  Time = distance /speed
  Time =250/125
  Time = 2hours to meet.
  They meet at 12.00 noon
• 10 years agoHelpfull: Yes(2) No(0)