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There r five boxes. In the first box we put some chocolates. Each box the number of choc is reduced by 1/4. The last box contains 4.Then the number of choc in the first box is
Read Solution (Total 1)
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- 1024 chocolates in 1st box.
choc reduced by 1/4.
Total no. of box, n=5
Formula to find no. of choc in 1st box = 4^n
Last Box = 4 chocolates.
That means, 4th box = 4*4 = 16 chocolates
3rd box = 16*4 = 64 chocolates
2nd box = 64*4 = 256 chocolates
1st box = 256*4= 1024 chocolates. - 12 years agoHelpfull: Yes(4) No(0)
CTS Other Question
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A) 1,2,3,4,5,6,7,8,9 B) 2,9,6,8,5,7,4,3,1 C) 4,9,5,1,3,8,7,2,6 D) 9,6,8,5,7,1,4,2,3
Out of 50 men in a town, 30 are Lions club members, 10 are Lions members as well as Rotary club members. There are 3 who do not belong either. Then how many Rotary club members are there?
(a) 15 (b) 18 (c) 20 (d) 25