A coffee seller has two types of coffee Brand A costing 5 bits per pound and Brand B costing 3 bits per pound. He mixes two brands to get a 40 pound mixture. He sold this at 6 bits per pound. The seller gets a profit of 33 1/2 percent. How much he has used Brand A in the mixture?

• he sold it 6 bits per pound.total pound=40.then selling price=40*6=240.it was given he made 33 1/2 percent profit,then the original price=180(x+x*33 1/2=240,then x=180)then 1st equation is 5A+3B=180,he mixes 2 brand to get 40 pound so 2nd eq. A+B=40,after solving these equations ,we will get A=30................
• 12 years agoHelpfull: Yes(13) No(12)
• Total mixture=40 pound
  selling price of 40 pound mixture=(40*6)=240bit
  cost price=(240*100)/(100+33.5)=179.77=180bit
  cost per pound=(180/40)=4.5bit
  using alligation formulae:-
  (n1/n2)=(5-4.5)/(4.5-3)=3:1
  so A=30..
  
• 9 years agoHelpfull: Yes(9) No(1)
• let x and y quantities of A and B respectively are mixed
  x+y=40
  his total selling price.....40*6=240
  his cost price ..............180 approx(as he makes 33.5 % profit)
  5x+3y=180
  solving u get x=30 and y=10
  hence ans 30 pounds
• 8 years agoHelpfull: Yes(5) No(2)
• 240-[5*x+(40-x)*3]=[5*x+(40-x)*3]*33 1/2%
  =>240-(2x+120)=(2x+120)*(67/2)*(1/100)
  =>24000-400x=134x+8040
  =>x=(15960/534)
  =>x=29.88
  x near about 30
  so, 30 pound of Brand A is mixed
• 9 years agoHelpfull: Yes(0) No(1)