if z=(log(base a)(log(base b)(a)))/(log(base b)(log(base a)(b)))

• Answer should be -> z= -ln(base a) b
• 9 years agoHelpfull: Yes(16) No(3)
• z=(log(base a)(log(base b)(a)))/(log(base b)(log(base a)(b)))
  => z=[log(base b)(a))/log(a)]*[log(b)/(log(base a)(b))]
  => z=[log(a)/{log(a)*log(b)}]*[{log(b)*log(a)}/log(b)]
  => Z=log(a)/Log(b)
  => Z=log(base b) (a) .....Ans
• 8 years agoHelpfull: Yes(6) No(3)
• plz upload the full problem.
• 9 years agoHelpfull: Yes(3) No(1)
• Hold your breath :p
  z=(log(base a)(log(base b)(a)))/(log(base b)(log(base a)(b)))
  Let log b base a = x
  then, log a base b = 1/x
  => log 1/x base a / log x base b
  => -log x base a / log x base b
  => - 1 / log a base x / 1 / log b base x
  => - log b base x / log a base x
  Ans = - log b base a [ using property ]
  Cheers :D
• 7 years agoHelpfull: Yes(3) No(0)
• heheeee mujhe nai mallooom I guess1
• 8 years agoHelpfull: Yes(0) No(0)
• z=(b^3/2)/(a^3/2)
• 8 years agoHelpfull: Yes(0) No(0)
• answer would be = -logb^a or log a^b
• 7 years agoHelpfull: Yes(0) No(0)
• please submit genuine solution
• 6 years agoHelpfull: Yes(0) No(0)