4 men can cross a bridge in 3,7,13, 17 minutes. Only two can cross the bridge at a time. The time taken by the two to cross the bridge is equal to the time taken by the slowest person of the two. Find the minimum time to all of them cross the bridge.

• First 17 and 7 going so that 7 will reach in 7 min remain 10
  Now 13 and 17 is going so that 17 I will reach in 10 min remain 3
  Now 13 and 3 is going so that both reached in 3 min. so total min to reach is 7+10+3=20
  
• 10 years agoHelpfull: Yes(9) No(1)
• 4 men can cross a bridge in 3,7,13, 17 minutes. Only two can cross the bridge at a time.
  
  3+7 cross in 7 mins...............total 7 mins so far
  3 min person comes back......... 10 mins.
  13+17 cross bridge in 17 min..............27 mins.
  7 min person comes back in 7 min..... 34 mins
  3+7 cross bridge in 7 mins............ 41 mins total
• 13 years agoHelpfull: Yes(2) No(21)
• answer is 24 as 1st time (3,7) pass so time is 7
  2nd time (13,17) will pass so time is 17
  so 7+17=24
• 10 years agoHelpfull: Yes(1) No(3)
• 20 minute
  
• 9 years agoHelpfull: Yes(1) No(0)
• Answer is 47
• 8 years agoHelpfull: Yes(0) No(0)