How many 5 digit no. can b formed wit digits 1, 2, 3,4,5,6 which r divisible by 4 and digits not
repeated

• Number can bedivisible by 4 if its last 2 digits are divisible by 4 so the possiblities are
  12,16,24,32,36,52,56,64= 8 possiblities
  Since 2 digits are occupied remainin g 3 blanks can be filled by 4 remaining digits i.e 4!
  Therefore the ans is 4!*8
  24*8=192
• 9 years agoHelpfull: Yes(18) No(0)
• number can divisible by 4 is 8 ways (12,16,24,32,36,52,56,64)
  last 2 digits occupied by 8 ways
  remaining 3 letters can be possible to filled in 4p3 ways
  i.e 4p3 * 8 = 24*8 = 192
  
• 9 years agoHelpfull: Yes(2) No(1)
• Vamshi priya----digits should be not repeated that is mentioned in question...so 192 is right answer.
• 9 years agoHelpfull: Yes(2) No(0)
• The question is for without repetition so we shouldn't take 44 into account
• 8 years agoHelpfull: Yes(2) No(0)
• Number can bedivisible by 4 if its last 2 digits are divisible by 4 so the posiblities are
  12,16,24,32,36,44,52,56,64= 9 posiblities
  Since 2 digits are occupied remaining 3 blanks can be filled by 4 remaining digits i.e 4!
  Therefore the ans is 4!*9
  24*9=216
  
• 9 years agoHelpfull: Yes(1) No(13)
• Why have u taken 4! @All
• 8 years agoHelpfull: Yes(1) No(0)
• pls explain
• 9 years agoHelpfull: Yes(0) No(1)
• @VAMSHI PRIYA -
  NOTE : NUMBERS ARE NOT REPEATED SO, 44 WILL NOT BE TAKEN INTO CONSIDERATION !!
  4!*8 =192
• 8 years agoHelpfull: Yes(0) No(0)
• - - - - -
  ( last 2 digits 1's and 10's place divisible by 4 i.e 12,16,24,32,36,52,56,64 total 8 ways(without repetition))
  ( 3rd digit 100th place 4 ways because already 2 digits are used)
  (4th place 1000's place 3 ways )
  (5th digit 10000's place 2 ways)
  so ans is 8ways*4ways*3ways*2ways =192
• 8 years agoHelpfull: Yes(0) No(0)