There are 9 balls of this one is defective. Find the minimum no. of chances of finding the defective one.

• 2 chance
  1.9 balls 3 parts 3 in each part
  Weight any two part if defective found then well and good else defective in the third part.
  2.now divide the defective part(3 balls) in another 3 parts 1 1 1
  weight any two if defective ball found ten well and good else 3 ball defective.
• 10 years agoHelpfull: Yes(19) No(5)
• 1 chance minimum for finding defective ball.
  
  If take 1st ball and it is defective.
  So, minimum 1 chance.
• 12 years agoHelpfull: Yes(6) No(18)
• we will divide into 2 weights 5 and 4
  that is one way
  5 will become 3 and 2
  and we will have to divide
  
  
  so answer is 3
• 12 years agoHelpfull: Yes(6) No(12)
• Minimum Chance is 1..( 9 balls. Juzt weigh 4-4, if it is equal then other one is defective. )
  Maximum chances is 3 ( weigh 4-4, if any one is higer, then divde by 2-2, and 1-1 finally u will get the defective one)
• 10 years agoHelpfull: Yes(3) No(1)
• min 2 chances are reqd to find defective ball.
• 13 years agoHelpfull: Yes(2) No(12)
• 9 balls. 1 is defective
  so, 9c1
  (i.e) 9/1
  answer is 9
• 10 years agoHelpfull: Yes(2) No(4)
• Minimum Chance is when he pick the ball in first chance only thus ..probability of getting a defective ball out of 9 is -> (1/9)
• 10 years agoHelpfull: Yes(1) No(1)
• minimum 3 chances to found the defective ball....
  we take 4+4 ball if there is any defective some change in this weight.
  we take the defective side and split into 2+2 then we can easily found the defective ball
• 9 years agoHelpfull: Yes(1) No(0)
• Min chance is 1. I faced this question in interview yesterday and i said the sol as follows:
  take 4 on each side of balance and if it shoes equal then the remaining one is defective.
• 10 years agoHelpfull: Yes(0) No(1)
• 9=(5,4) again divide 5 in (3,2) ist chance-> we aplly in 2. now we have 4+3 i.e 7 ball, again divide 7=(4,3). now divide 3=(2,1) in 2nd chance we can get again defective one. now we have 4 balls now divide into 4=(3,1) in 3rd chance 3=(2,1) we can get the defective one. IN ALL ABOVE PROCESS WHERE THERE IS 1 BALL NO NEED TO CHECK SO NEGLECTED.
• 10 years agoHelpfull: Yes(0) No(0)
• min. no. of chances of finding the defective ball out of 9 balls is 1
• 9 years agoHelpfull: Yes(0) No(0)