Diamonds value is proportional to its weight. When the diamond broke wts of pieces in ratio 1:2:3;4:5. Total loss in value is 85,000. What is the value of the diamond twice the wt of the original diamond.

• wts value
  x x^2
  2x 4x^2
  3x 9x^2
  4x 16x^2
  5x 25x^2
  -------------------------------
  15x 55x^2
  
  
  
  
  original wt=15x
  original value=225x^2
  loss in value due breakage=225x^2-55x^2=170x^2
  170x^2=85000=>x^2=500
  wt of diamond twice the original wt=2(15X)=30x
  value=$900x^2=900*500=$450000
• 10 years agoHelpfull: Yes(1) No(0)