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AC CG GO OE ??
a)EJ b)EI c)EL d)None
Read Solution (Total 7)
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- A C
1 (1*2)+1=3(C)
C G
3 (3*2)+1=7(G)
G O
7 (7*2)+1=15(0)
O E
15 (15*2)+1=31-26=5(E)
E ?
5 (5*2)+1=11(k)
so ans=EK - 11 years agoHelpfull: Yes(14) No(0)
- ans is A (EJ)
2^1-1=1 AC
2^2-1=3 CG
2^3-1=7 GO
2^4-1=15 OE
2^5-1=31 EJ - 13 years agoHelpfull: Yes(7) No(9)
- ANS: EK
EXPLANATION :AC
[1 AND 3]
CG
[3 AND (3+3+1)]
GO
[7 AND(7+7+1)]
OE
[15 AND(15+15+1)]
EK
[31 AND (31+31+1)] - 10 years agoHelpfull: Yes(0) No(0)
- ans:d
since ans is EH
- 9 years agoHelpfull: Yes(0) No(0)
- ans=EK
d) none - 9 years agoHelpfull: Yes(0) No(0)
- ans==ek
so None - 9 years agoHelpfull: Yes(0) No(0)
- AC CG GO OE--------------->
Consider AC and CG....as words
each letter consists of 2 letters...
in the first word the first letter is A and the second letter is C---which tells us a gap of 1 alphabet is used.
Coming to second and third words ,we can see that the first letters are the last letters of previous words...so in that we can conclude that the first letter of the required word is E.
Coming to second letter we could see from the first second third and fourth word that a gap of 1,3,7,15..then it shoud be 31(add 2,4,8,16---->>>>multiplying 2 with product obtained) is used so if you use the same method ...you cannot find the answer in options provided. So None - 9 years agoHelpfull: Yes(0) No(0)
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