Find out the distinct numbers that can be formed by 2, 3, 7, 6 that should be divided by 4?

• 8 is the answer ,vignesh is wrong
• 10 years agoHelpfull: Yes(6) No(1)
• 64 distinct numbers can be formed.
  Expln: For a number to be divisible by 4, last two digits must be
  divisble by 4.
  so 32,36,72,76 are the only for possible combinations at
  the last two positions.(i.e., 4 possibilities)
  The first position can be filled in 4 ways = 4c1
  similarly,second position also can be filled in 4 ways = 4c1.
  so totally = (4c1)*(4c1)*4(possible chances)
  =4*4*4
  =64 chances.
• 13 years agoHelpfull: Yes(4) No(8)
• possible number is 8.
  numbers are
  3276,2376,7632,6732,6372,3672,7236,2736
  these r possible number.
• 10 years agoHelpfull: Yes(0) No(0)
• 128 is answer.....
  last digit is either 2 or 6 divisible by 4..........(4*4*4)*2=128
  
• 9 years agoHelpfull: Yes(0) No(0)
• 6732,7632,2736,7236,3672,6372,3672,6372,2376,3276---- 8 numbr !
• 9 years agoHelpfull: Yes(0) No(0)
• 8 is the answer.
  divisibility by 4 says that the last two digits should be divisible by 4.
  hence,32,36,72,76 can the ending digits. and 8 no.s can be formed.
• 9 years agoHelpfull: Yes(0) No(0)
• _ _32,_ _36,_ _72,_ _76 are the possible last two digits there fore 8 ways
• 9 years agoHelpfull: Yes(0) No(0)
• _ _ 3 6
  _ _ 3 2
  _ _ 7 6
  _ _ 7 2
  
  2 places left 2 digits left so 2P2
  and 2 cases so
  2*4=8 ans
• 5 years agoHelpfull: Yes(0) No(0)