The value of binary 11111 is

a.2^4-1
b.2^4
c.2^5
d.2^5-1

• answer is D, because (11111) is equivalent to 31, which is equal to 2^5-1
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• 11111 has to be converted to decimal
  ie (1*2^0)+(1*2^1)+(1*2^2)+(1*2^3)+(1*2^4)=1+2+8+16
  =31
  ie (2^5-1)
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• ans is d) 2^5-1;
  2^0+2^1+2^2+2^3+2^4=31=2^5-1
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