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Two consecutive sides of a cube were painted with dark colour, and the opposite faces were painted with white. Rest of them is painted with yellow. The cube is divided into 64 equal parts. How many of them are painted in (i) one side only (ii) two side only?
Read Solution (Total 3)
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- i)24
II) 24 - 10 years agoHelpfull: Yes(5) No(0)
- its easy from formula
(i) one side only = 6*(N-2n)^2
(ii) two side only = 12*(N-2n)
Where N is cube root of(64)= 4
and n is 1 for equal parts.
So ans will be 24 and 24. - 10 years agoHelpfull: Yes(2) No(0)
- Since all the sides are painted , on each face :
No. of cubes with 1 side painted = no. of middle cubes on each face
=2^3=8
So, total no. of cubes painted one side only are =6*8=48
Similarly , no. of cubes painted 2 sides only =12*2^2=48 - 12 years agoHelpfull: Yes(0) No(5)
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