A can do a piece of work in 12 days and B can do a piece of work in 18

A's 1 day work=1/12,B's 1 day work =1/18;
(A+B) 1 day work=1/12+1/18=5/36;
they can finish the work in=36/5=7.2
ans=7.2
13 years agoHelpfull: Yes(18) No(0)

1/12+1/18=5/36. NO OF DAYS=36/5=7.2 HENCE OPTION B
12 years agoHelpfull: Yes(1) No(0)
LCM of A,B=36
so A's 1day work=36/12=3
B's one day work=36/18=2
A+B one day work=5
together=36/5=7.2
9 years agoHelpfull: Yes(1) No(0)
xy/x+y where x=12 y=18=>36/5=7.2
7 years agoHelpfull: Yes(1) No(0)
A'S 1 day work=1=1/12 and B's 1 day work =1/18
then A+B's 1 day work is 1/12+1/18=5/36
so A and B togher completed the work in 7.2 days
10 years agoHelpfull: Yes(0) No(0)
1/12+1/18 = 5/36
then total time taken = 36/5 = 7.2 days
10 years agoHelpfull: Yes(0) No(0)
Option B

1/12+1/18=5/36=1/7.2
so 7.2 is the answer
9 years agoHelpfull: Yes(0) No(0)
7.2 days...............
9 years agoHelpfull: Yes(0) No(0)
7.2 days ans
9 years agoHelpfull: Yes(0) No(0)
LCM of A,B=36
so A's 1day work=36/12=3
B's one day work=36/18=2
A+B one day work=5
together=36/5=7.2
9 years agoHelpfull: Yes(0) No(0)

A can do a piece of work in 12 days and B can do a piece of work in 18 days how many days will the work be completed if both of them work together?
a)15
b)7.2
c)7.7
d) 7.4