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What is te smallest number which when decreased by 5 is divisible by 21, 27, 33, and 55?
a] 1490
b] 10400
c] 15490
d] none
Read Solution (Total 1)
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- 10400
LCM of 21, 27, 33, and 55 = 10395
hence required number = 5+10395= 10400 - 13 years agoHelpfull: Yes(18) No(1)
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