A train and A Cyclist reaches a station every day at the same time. One day the Cyclist starts 20 minutes late from his house.On his way to station the train crosses him at 5 miles before station.The speed of cyclist is 12mph. Find the speed of the train

• In 20 min, the cyclist travels 4 miles. The train crossed him at a distance of 5 miles from station. After the train had reached the station, the cyclist should be 4 miles away (20 min late). So for 1 mile of cyclist, train travels 5 miles. Train is 5 times fast. So ans is 60mph
• 13 years agoHelpfull: Yes(17) No(3)
• The other day cyclist was late by 20 mint.
  To cover a dist. of 5miles (@12mph) he need 25 minutes.
  At the meantime he meets the train (i.e before 5miles from their actual meeting point)
  If he is by time , in another 5mnt (25mnt -20mnt late ) he would have met the train.
  
  It implies that the train is running for 5 minutes (train speed being same)
  5miles / 5mnts => 60mph.
• 9 years agoHelpfull: Yes(2) No(0)
• could you explain this in a clear manner..So for 1 mile of cyclist, train travels 5 miles. Train is 5 times fast.
  
• 9 years agoHelpfull: Yes(0) No(1)
• In 20 min, the cyclist travels 4 miles.
  Train crossed him 5 miles from station.
  
  If he starts as usual he and train will meet station.
  So, In 20 min train reaches station.
  train is 5 miles from station.
  so train velocity =5miles/(20 min)
  converting into mph it is
  15 mph
• 9 years agoHelpfull: Yes(0) No(3)
• Very Nice Problem
• 9 years agoHelpfull: Yes(0) No(1)