A group is divided into three. The first group is persons of 5'6 height and second and third r 6'0 and 6'6 respectively. There r totally 130 peoples, 50 of them r 5'6 and 65 of them r 6'6, 10 of them r 5'6 and 6'6, 15 of them r 5'6 and 6, 20 of them r 6'6 and 6, and 5 of them r all the three.
How many of them r 6 feet?

• 130-30-20-10=70
• 11 years agoHelpfull: Yes(4) No(4)
• Ans=55
  
  3 groups are A,B,C
  n(A)=50 , n(C)=65
  n(A intesection B)=15
  n(A intesection C)=10
  n(B intesection C)=20
  
  130 = 50+65+n(B)-15-10-20+5
  n(B)=55
• 10 years agoHelpfull: Yes(2) No(0)
• total number of people=130
  number of persons of height 5'6=50
  number of persons of 6'6 height=65
  number of people of 5'6 and 6'6 height=10
  number of people of 5'6 and 6'0 height=15
  number of persons of all 3 heights=5
  number of people of height only 5'6=(number of people of height 5'6)-(number of people of all heights)- (number of people of heights 5'6 and 6'0)- (number of people of heights 5'6 and 6'6) =50-5-15-10=20
  
  number of people of height only 6'6=(number of people of height 6'6)-(number of people of all heights)-(number of people of heights 6'0 and 6'6)=(number of people of heights 6'6 and 5'6)=65-5-20-10=30
  
  number of persons of height 6 feet=(total number of people)-(number of people of heights only 5'6)-(number of people of heights only 6'6)-(number of people of heights 5'6 and 6'6)=130-20-30-10=70
• 10 years agoHelpfull: Yes(2) No(0)
• Solution : 15 of them are 6'0 height.
  Explaina : Total number of peoples=130
  Consider X as 5'6 height, X = 50
  Y as 6'6 height, Y = 65
  Z as 6'0 height, Z = ?
  Therfore, Z= Total number of peoples - (X+Y)
  = 130 - (50+65)
  = 130 - 115
  = 15
• 13 years agoHelpfull: Yes(0) No(17)