exam
Maths Puzzle
Numerical Ability
I'm stuck: with 2 problems
x^3 - 5 = 3
3 3x - 2
- =1 -------
4 x + 1
would the common denominator be 4(x+1)? but that doesn't make sense ...I'm lost
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exam Other Question
Multiply:
(√[3] + 2√[5])(6√[3] - √[5])
?????
Tell wheather the given value of the varible is a solution of the equation.
-2(3x+7)=-3(2x+8);x=-5.
Thanks u for all the help!