. 8 man work for 6 days to complete a work. How many men are required to complete same work in 1/2 day.
Ans. 96 men.

• 96men required..
  To complete a work for 6 days, 8 mens required.
  For complete a work for 1 day = 6*8
  = 48mens
  for complete a work in half a day(1/2) = 48*2
  = 96mens
• 13 years agoHelpfull: Yes(10) No(0)
• Total man work days= 8*6=48
  So, to complete the work in half(1/2) days= 2*48 men required=96 men.
• 13 years agoHelpfull: Yes(0) No(0)
• 8m=6d
  0.5d=?
  8/x=6/0.5
  8=12x
  .1=7.5day
  
  x=96m
• 13 years agoHelpfull: Yes(0) No(0)
• (m1*t1)/w1=(m2*t2)/w2
  work is constant
  8*6=x*0.5
  x=96 mens
• 10 years agoHelpfull: Yes(0) No(0)
• 8men = 6days
  8 men do 1/6 th work in 1 day
  so 1 man does 1/8 * 1/6 work =1/48 work in 1 day
  in 1/2 day he does 1/96 th work
  
  To complete the work (1) in 1/2 day requires 96 men
  
  So answer is 96
• 8 years agoHelpfull: Yes(0) No(0)
• 8 men=6 days;
  8 men one day work=1/6;
  1 man one day work =1/6*1/8;
  to complete in half day=1/6*1/8*1/2=
  96 men
• 8 years agoHelpfull: Yes(0) No(0)
• 96
  8*2*6=x
• 8 years agoHelpfull: Yes(0) No(0)