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Eric throws two dice, and his score is the sum of the values shown. Sandra throws one die, and her score is the square of the value shown. What is the probability that Sandra’s score will be strictly higher than Eric’s score?
a. 137/216
b. 17/36
c. 173/216
d. 5/6
Sol: A

Read Solution (Total 1)

Let us say Sandra thrown 6, Then her score is 36. So what ever Eric throws it is less than 36 ( max eric throws is 12, min 2).
So If sandra throws 6, 5, 4 then her score is more. In each of these cases Eric can throw the dice in 6 x 6 = 36 ways. So total possibilities for these three numbers = 36 x 3 = 108 ways.
Now If sandra throws 3, her score is 9. So Eric should throw 2 to 8. So number of possibilities 1 + 2 + 3 + 4 + 5 + 6 + 7 + 5 = 26.
If sandra throws 2, her score is 4. So eric can throw 2 or 3. Possibilities 1 + 2 = 3
If sandra throws 1, Eric scores more.
So required outcomes = 108 + 26 + 3 = 137
Total outcomes = (6 x 6) x 6 = 216.
Probability that Sandra wins = 137 /216.
10 years agoHelpfull: Yes(8) No(2)

TCS Other Question

What is the next number of the following sequence..
1,3,8,15,27,___
A permutation is often represented by the cycles it has. For example, if we permute the numbers in the natural order to 2 3 1 5 4, this is represented as (1 3 2) (5 4). In this the (132) says that the first number has gone to the position 3, the third number has gone to the position 2, and the second number has gone to position 1, and (5 4) means that the fifth number has gone to position 4 and the fourth number has gone to position 5. The numbers with brackets are to be read cyclically. If a number has not changed position, it is kept as a single cycle. Thus 5 2 1 3 4 is represented as (1345)(2). We may apply permutations on itself If we apply the permutation (132)(54) once, we get 2 3 1 5 4. If we apply it again, we get 3 1 2 4 5 , or (1 2 3)(4) (5) If we consider the permutation of 7 numbers (1457)(263), what is its order (how many
times must it be applied before the numbers appear in their original order)?
a. 12
b. 7
c. 7! (factorial of 7)
d. 14