A driving license number has 6 digits (between 1 to 9). The first two digits are 12 in that order, that third digit is bigger than 6, the fourth one can be equally divided by 3 and the fifth digit is 3 times bigger than sixth one. How many license numbers can be made using this arrangement?
a)27
b)36
c)72
d)112

• 27 numbers are possible.
  
  First two digits are fixed,
  Third digit can have 3 values 7,8,9.
  4th digit can have 3 values 3,6,9.
  5th and 6th digit can have 3 combinations like 31, 62,93.
  
  so total combinations are 3*3*3=27
• 13 years agoHelpfull: Yes(22) No(1)
• 36
  
  Third digit can have 3 values 7,8,9.
  4th digit can have 3 values 3,6,9
  5th digit can have 2 values 4 ,8
  6th digit can hv 2 values 1,2.
  
  so total possible license numbers = 3*3*2*2 =36
• 13 years agoHelpfull: Yes(9) No(13)
• Ans. 27
  
  First two digits are 1 & 2
  Third digit can either be 7 or 8 or 9
  Fourth digit can be 3, 6, 9
  since fifth digit is three times bigger than sixth digit then the possible combinations are 31 or 62 or 93
  Total license number arranged using this arrangements = 3*3*3 = 27.
• 13 years agoHelpfull: Yes(4) No(2)
• 36 numbers are possible.
• 13 years agoHelpfull: Yes(3) No(2)
• Ans is 36
  First digit can have one value 1
  Second digit can have one value 2
  Third digit can have three values 7,8,9
  Fourth digit can have three values 3,6,9
  Fifth digit can have two values 4,8
  Sixth digit can have two values 1,2
  Total no' of Possibilities=1*1*3*3*2*2=36
  
• 13 years agoHelpfull: Yes(2) No(3)
• Ans. 27
  
  First digit is 1
  Second digit is 2
  Third digit can be 7 or 8 or 9
  Fourth digit can 3, 6, 9
  If fifth digit is three times sixth digit then Fifth and Sixth digits can be in pairs as (3,1),(6,2),(9,3)
  So the numbers can be
  127331,127362,127393,127631,127662,127693,127931,127962,127993
  128331,128362,128393,128631,128662,128693,128931,128962,128993
  129331,129362,129393,129631,129662,129693,129931,129962,129993
  --------------------------------------------------------------------------------
  If fifth digit is three times bigger than sixth digit then fifth and sixth digits can be in pairs as (4,1),(8,2)
  Then numbers will be
  127341,127382,127641,127682,127941,127982
  128341,128382,128641,128682,128941,128982
  129341,129382,129641,129682,129941,129982
  
  Then answer will be 18 which is not given in options.
  
• 13 years agoHelpfull: Yes(2) No(3)