SSC Government Jobs Exams Numerical Ability Geometry

Two chords AB and CD of a circle whose centre is O,meet at the point P and angle AOC=50 , angle BOD = 40,then the value of Angle BPD is ??

Read Solution (Total 3)

angle BOD =40.Therefore angle BCD =20(angle at any point on the circle for the same arc is half of that at the centre).Similarly as angle AOC=50,angle ABC=25.In triangle PBC,angle BPC=(180-20+25)=135. As angle BPC and BPD make a linear pair,angle BPD = 180-135=45.
9 years agoHelpfull: Yes(3) No(1)

angle B0D=2*angle BPD
therefore, angle BPD= Angle BOD/2=40/2=20
since,the angle subtended by an arc of a circle at the center is double the angle subtended by it at any point on the remaining part of the circumference.
13 years agoHelpfull: Yes(1) No(18)
For this problem we have a ready made formula,
9 years agoHelpfull: Yes(0) No(0)

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