Two cans A & B contain 25% & 30 % of milk. If 6 parts of can A and 4 parts of can B acre mixed in a can C. What is the proportion of milk in can C.

• 27%
  suppose we take 10 lits of solution in tank A and B then
  25% of in A is 2.5 lits and 30% in B is 3 lits milk
  6 parts of A can have 1.5 lits of milk and 4 parts of B have 1.2 lts of milk so
  totally 2.7 lits of milk in c i.e 27%.
• 12 years agoHelpfull: Yes(6) No(4)
• Ans: 27%
  
  Can C contains 6 parts from Can A and 4 parts from Can B.
  Can C contains milk from Can A = (6/10)*(25/100)= 3/20 parts
  Can C contains milk from Can B = (4/10)*(30/100)= 3/25 parts
  Total milk in Can C = (3/20)+(3/25) = 27/100 parts = 27%
• 12 years agoHelpfull: Yes(6) No(0)