In how many ways can we arrange 7 different things to 3 people All of them must get atleast one

(n+r-1)C(r-1) where n=7-3=4, r=3
so,6C2= 15
9 years agoHelpfull: Yes(6) No(7)
answer is 1806
explanation here http://math.stackexchange.com/a/527430
9 years agoHelpfull: Yes(5) No(1)
: Division of m+n+p objects into three groups is given by (m+n+p)!/m!×n!×p!
But 7 = 1 + 3 + 3 or 1 + 2 + 4 or 1 + 1 + 5
So The number of ways are (7)!/1!×3!×3!×12! + (7)!/1!×2!×4! + (7)!/1!×1!×5!×12! = 70 + 105 + 21 = 196
8 years agoHelpfull: Yes(3) No(1)
We can arrange in 15 ways
9 years agoHelpfull: Yes(1) No(6)
we must atleat 1 to 3 people.. ie total no of things is 3.. now the remainging things is 4.. so the formula is n=4 ,r=3 therefore (4+3-1)C(3-1)=15
9 years agoHelpfull: Yes(1) No(2)
for this kind of prob the formula is n+r-1 c r-1..
here n=7
and r=3..
so the sol is 9c2=36
9 years agoHelpfull: Yes(1) No(1)
I think it is :
7p3=210..bcoz it is asked to arrange so arrangement trends to permutation r8!!!
9 years agoHelpfull: Yes(0) No(3)
7p3 bcoz of arrangement
9 years agoHelpfull: Yes(0) No(2)
a+b+c=7
all of them get at least one so 7-3=4,
a+b+c=4
n+r-1 C r-1 = 7+3-1 C 3-1 = 15
9 years agoHelpfull: Yes(0) No(0)
answer may be 840
9 years agoHelpfull: Yes(0) No(0)
formula is (n-1)C(r-1). as all of them must get atleast one. so answer is (7-1)C(3-1)=6C2=15
9 years agoHelpfull: Yes(0) No(0)
(n+r-1)C(r-1)
9C2=36
8 years agoHelpfull: Yes(0) No(1)

In how many ways can we arrange 7 different things to 3 people. All of them must get atleast one.