has anyone solved problem related to geometry asked on dec 21 which is "the area of rhombus is 400 & its diagnol is 80 its perimeter is equal to perimeter of circle then what is the area of circle", options are something like 1)6400 2)10000 3)2000 4)65000

• ans is 2067.75 as => area of rhombus is PQ/2 =400 ;;
  one diagonal is given =80 ;;
  so 80*Q/2=400 ;; Q=800/80=10 ;;
  rhombus perimeter = perimeter of circle
  4a = 2*pi*r
  a= sqrt of(P^2+Q^2) /2 = sqrt of (80^2+10^2)/2 = 40.31
  then perimeter of rhombus is 4a => 4*40.31=161.24
  161.24=2*pi*r
  25.65=r
  in this problem asked to find area of circle =>pi*r^2
  22/7 *(25.65)^2 = 2067.75
• 10 years agoHelpfull: Yes(17) No(2)
• this is not the correct question
  the ques ws given area of rhombus = 2400
  and after solving the answer will be 10000/pi
• 10 years agoHelpfull: Yes(9) No(0)
• area of rhombus= (1/2)*d1*d2 ............. d1 and d2 are length of diagonals
  d1=80 ; and area =400 so d2=10
  
  now if we draw a diagram using these d1 and d2 we will get the value of side of Rhombus=5*(sqrt 65)
  
  so if circle radius is R then 2*pi*R = 4*5*(sqrt 65)
  from above equation R=[ 20*(sqrt 65) ] / [2*pi]
  so area of circle=> pi*R*R= 6500/pi
• 9 years agoHelpfull: Yes(6) No(0)
• one diaonal is 80,it will bisect other one at right angle. So by pythagoras we will get half of the second diagonal = 30 and side of rhombus = 50.So the perimeter will be 200.
  Now for the circle 2*pi*r= 200.Thus we can get the area. But the answer does not match any of the options
• 10 years agoHelpfull: Yes(3) No(1)
• none of the option is correct
  area of rhombus=product of diagonals/2
  d1=80
  d2=10
  perimeter=4*side
• 9 years agoHelpfull: Yes(1) No(0)
• 2069.09
  (d1*d2)=800 so,d2=10
  a=((6400+100)^0.5)
  4a=2*3.14*r
  so,area=2069.09
• 10 years agoHelpfull: Yes(0) No(0)