If m and n are whole numbers such that mn = 121, the value of (m - 1)n + 1 is:

A. 1 B. 10

C. 121 D. 1000

• Pls check
  
  case i) (m-1)n + 1 = (11-1)11+1 = 121
  
  I think
  (m-1)n + 1 = (11-1)11+1 will be equal to 111.
  
  One more case can be there.
  when m=1, n=121, then
  (m - 1)n + 1 = (1-1)*121 +1 = 0+1 =1
  
  when m=121, n=1,then
  (m-1)n+1 = (121-1)(1)+1 = 121
  
  so two possible answers. 1 and 121
  
• 13 years agoHelpfull: Yes(36) No(5)
• mn = 121 and m and n are both whole number, which means m and can be any integer >= 0
  Now this results in three cases
  1. m = 11 and n = 11
  then, (m-1)n+1 = (11-1)*11 + 1 = 111
  not in optipns
  2. m = 1 and n = 121
  then, (m-1)*n + 1 = (1-1)*121 + 1 = 1
  i.e. option A
  3. m = 121 and n = 1
  then, (m-1)*n + 1 = (121-1)*1 + 1 = 121
  i.e. option C
  
  Hence answer is A and C both
  Hence
• 13 years agoHelpfull: Yes(15) No(0)
• Correct answer is (c) i.e. 121
  
  because if mn = 121
  
  m=121,n=1
  
  or
  
  m = 11, n = 11
  
  case i) (m-1)n + 1 = (11-1)11+1 = 121
  
  case ii) (m-1)n+1 = (121-1)(1)+1 = 121
  m=11
  
• 13 years agoHelpfull: Yes(14) No(29)
• mn=121 121 can be obtained by multiplying 121*1
  m=121,n=1
  (m-1)n+1=121
  if we choose m=1 and n=121
  then the answer will be 1
  so there r two possible answers 1 and 121
• 13 years agoHelpfull: Yes(3) No(1)
• actual question is m^n=121,the value of (m-1)^n+1
  11^2=121
  (11-1)^2+1=10^3=1000
  
• 8 years agoHelpfull: Yes(3) No(1)
• Ans. C. 121
  
  mn = 121
  As m and n are whole numbers so m and n can have values from
  0,1,2,3,4,......................
  So mn = 121 =>
  m=11 and n=11
  or
  m = 121 and n = 1
  
  When So m=11 and n=11
  (m-1)n + 1 = (11-1)11+1 = 121
  
  When m = 121 and n = 1
  (m-1)n+1 = (121-1)(1)+1 = 121
  
  
• 13 years agoHelpfull: Yes(2) No(8)
• Correct answer is (A)
  Solution: given that mn=121,
  n=121/m;
  so,
  (m-1)121/m + 1
  = 122-121/m
  Since m is a whole num
  So,assuming the lowest possible value i.e. 1,
  122-121=1 ,which is the ans.
• 12 years agoHelpfull: Yes(1) No(0)
• given mn=121.so m!=11 and n!=11 (m!=n).
  so m=121 and n=1 or n=121 and m=1.
  so ans is 121.
• 12 years agoHelpfull: Yes(1) No(2)
• guys first of all it is m^n hence it is 11^2 and therefore m=11 and n=2 so it is 1000
• 10 years agoHelpfull: Yes(1) No(0)
• Hello !
  
  M=1 and N=121 also possible.If m=1 and n=121 ,ans =1
• 13 years agoHelpfull: Yes(0) No(0)
• as mn=121
  (m-1)n+1= mn-n+1=121-n+1= 122-n, but n=121/m => 122-121/m=122m-121 => m=1 and n=121
  => (m-1)n+1 = (1-1)121+1=0*121+1=1
  Solution is: A. 1
• 9 years agoHelpfull: Yes(0) No(0)
• the question is:-
  If m and n are whole numbers such that m^n = 121, the value of (m - 1)^n + 1 is:-
  and the answer is:-
  D. 1000
  as m=11 and n=2 so,
  (11-1)^(2+1)=10^3=1000
• 7 years agoHelpfull: Yes(0) No(0)
• 1 and 121
  mn-n+1=121
  mn=121
  substitute and verify
  
  ANS: C
• 7 years agoHelpfull: Yes(0) No(0)