I the numerator o a fraction is increased by 200% and denominator is increased by 250% the resultant fraction is 3/14. What is the original fraction?
a)1/2 b)3/4 c)1/4 d)1/8

• Ans. c) 1/4
  
  if the original fraction is x/y then after increasing numerator by 200% and denomenator by 250% new fraction will become 3x/3.5y
  
  3x/3.5y = 3/14 => x/y = 1/4 , Hence original fraction is 1/4
• 13 years agoHelpfull: Yes(19) No(0)
• Answer : c) 1/4
  
  Reason :
  
  Let P and Q be the original numerator and denominator respectively.
  
  P when increased by 200% becomes, P + P(200/100) = P (100 + 200)/100 = 300P/100
  
  Q when increased by 250% becomes, Q + Q(250/100) = Q (100 + 250)/100 = 350Q/100
  
  According to the question, (300P/100) / (350Q/100) = 3/14
  
  Or 300P/350Q = 3/14
  
  Or P/Q = (3/14) x (350/300) = 25/100 = 1/4
• 12 years agoHelpfull: Yes(7) No(0)
• let the original fraction be a/b
  according to the given condition,
  
  (1+(200/100))*a 3
  ---------------- = --
  (1+(250/100))*b 14
  
  3a*2 3
  ---- = --
  7b 14
  
  a 1
  -- = --
  b 4
• 10 years agoHelpfull: Yes(1) No(0)
• (3/14)*(350/300)=1/4
• 10 years agoHelpfull: Yes(1) No(0)
• Ans. c) 1/4
  
  if the original fraction is x/y then after increasing numerator by 200% and denomenator by 250% new fraction will become 3x/3.5y
  i.e., x+x*200%/y+y*250% =3/14
  =>x+x(200/100)/y+y(250/100) =3/14
  =>x+2x/y+2.5y =3/14
  
  3x/3.5y = 3/14 => x/y = 1/4 , Hence original fraction is 1/4
  
• 10 years agoHelpfull: Yes(0) No(0)