MCA Exam

A rich merchant had collected many gold coins. He did not want anybody to know about them. One day, his wife asked, "How many gold coins do we have?" After pausing a moment, he replied, "Well! If I divide the coins into two unequal numbers, then 37 times the difference between the two numbers equals the difference between the squares of the two numbers." The wife looked puzzled. Can you help the merchant's wife by finding out how many gold coins.

Read Solution (Total 2)

if x is no. of coins, he divide into unequal number,
let x=x1+x2
given condition,
37(x1-x2)=(x1^2-x2^2)
37(x1-x2)=(x1+x2)(x1-x2) b'c0z (a^2-b^2)=(a+b)(a-b)
x1-x2 cancel on both side we remain with
37=(x1+x2)=x
so no. of coins=37
13 years agoHelpfull: Yes(18) No(4)

Let Merchant has x coins, he divides x coins into unequal numbers y and z where y>z.
Then x=y+z
As per given condition,
37(y-z)=(y^2-z^2)
37(y-z)=(y+z)(y-z)
=> 37=(y+z)= x the total no. of coins
So no. of coins merchant has =37
13 years agoHelpfull: Yes(7) No(0)

MCA Other Question

5 sea pirates have 100 gold coins and want to share it. They propose a plan.
The senior most one has to propose an idea, if at least 50 % agree, the coins r shared accordingly. else the senior is killed and the next senior most is asked to present a plan and so on .
note, all the guys r very clever and very greedy and dont want to lose the coins, and dont want to die. Form a way to share the money. Can you find a five digit number that, if you place a 9 at the beginning to make a new number, is fours times larger than if you place the 9 at the end instead?