Q is not equal to zero and k = (Q x n - s)/2 find n?
(a) (2 x k + s)/Q (b) (2 x s x k)/Q (c) (2 x k - s)/Q
(d) (2 x k + s x Q)/Q (e) (k + s)/Q

• Ans. (a) (2 x k + s)/Q
  
  k = (Q x n - s)/2 => Q x n - s = 2 x k => Q x n = 2 x k + s => n = (2 x k + s)/Q
• 12 years agoHelpfull: Yes(33) No(1)
• given that k=(q * n - s)/ 2
  2k=q * n-s
  2k+s=q * n
  n=(2k+s)/q so, option (a) is correct
• 12 years agoHelpfull: Yes(11) No(2)
• ANSWER IS (a)..
  k=(Q*n-s)/2 ---->CROSS THE 2 TO LEFT SIDE
  2*k=Q*n-s ----> -S GOES TO LEFT SIDE AS ADDITION +S
  2*k+s=Q*n ----> MULTIPLICATION OF Q WILL BE DIVISION OF LEFT SIDE
  n=(2*k+s)/Q ---> FINAL ANSWER..
• 12 years agoHelpfull: Yes(4) No(1)
• k=(Q*n-s)/2 priority of operation (BEDMAS-B-brace,E-exponent,D-division,M- multiplication,A-addition,S-subtraction)
  2*k=(Q*n-s)
  then Q*n is operated as Qn then -s move to that side as +s
  (2*k+s)=Q*n
  then n=(2*k+s)/Q
  
  answer is (a)
  
• 12 years agoHelpfull: Yes(2) No(0)
• given: k=(qn-s)/2
  ans:
  2k=(qn-s)
  2k+s=qn
  (2k+s)/q=n
  
  
  ans: n=(2k+s)/q
• 12 years agoHelpfull: Yes(2) No(0)
• a)2*k+s/q,
• 10 years agoHelpfull: Yes(1) No(1)
• the answer is option a.
• 9 years agoHelpfull: Yes(1) No(0)
• given,
  k=(Qxn - s)/2
  so,by solving we get,
  n=(2xk+s)/Q
• 9 years agoHelpfull: Yes(0) No(0)
• (2 x k + s)/Q
  
  Answer is A
  http://callinterview.com/questions-answers/q-is-not-equal-to-zero-and-k-q-x-n-s2-what-is-n/
• 8 years agoHelpfull: Yes(0) No(0)