During a Pizza buffet where A eats more times 2.4 than B, and B eats 6 times less than C.find the leat number of times all the three has to eat.

• A eats more than B if B eats 1 times than the ratio of A and B is A:B is 2.4:1 or 12:5 and as B eat 6 times less the C the the ratio of B : C is 5:30 the the least number of times all three has eat is the LCM of A,B,C that is 60 ..
• 13 years agoHelpfull: Yes(12) No(0)
• as we have to find least number of times all three have to eat,
  so we take A eats 2.4 times more than B
  & B eats 6 times less than c
  a:b=1:2.4
  b:c=6:1(as b eats 6 times less than c)
  so, a:b:c=10:24:4
  so the answer is lcm of 10,24,4=110.
  
• 13 years agoHelpfull: Yes(1) No(12)
• 2.4:1:6 i.e. 12:5:30. Minimum 60 times(by taking LCM) one has to eat.
• 12 years agoHelpfull: Yes(1) No(1)
• A eats 2.4 times more than B, A:B = 2.4:1 = 24:10 = 12:5
  B eats 6 times less than C, B:C = 1:6 = 5:30
  Thus A:B:C = 12:5:30
  least number of times to eat = LCM(12,5,30) = 60
• 10 years agoHelpfull: Yes(1) No(0)