X varies inversely as square of y Given that y 2 for x 1 The value of x for y

x varies inversely as square of y.
we have
x = k/y^2
Given that x = 1, y = 2
then
1 = k/2^2
k =4

when y is 6
x= k/6^2
x = 4/36
x = 1/9.... option D
12 years agoHelpfull: Yes(8) No(0)
Ans; d)1/9
x varies inversely as square of y. So
x = k/y*y, where k is constant
Further it is given that for x = 1, y = 2
As per given condition
1 = k/2*2 => 1*4 = k => k = 4
So, when y is 6
x = 4/6*6 => x = 1/9.
12 years agoHelpfull: Yes(3) No(0)
x varies inversely with y
we have
x = k/y
When x is 1, y is 2
we have
1 = k/2
k =2

x= k/y
when k=2, y =6
x= 2/6 = 1/3 ... option C
12 years agoHelpfull: Yes(2) No(10)
x varies inversely square of y
so,x=k/y*y
y=2 for x=1
so,1=k/2*2
k=4
now,y=6
so,x=4/36=1/9
ans:D
12 years agoHelpfull: Yes(1) No(1)
x=c/y^2;since given that x=1,y=2,then
1=c/4=>c=4. again given that x for y =6 then x=4/36=>1/9
11 years agoHelpfull: Yes(1) No(1)
C)1/3
x varies inversely with y
we have
x = k/y
When x is 1, y is 2
we have
1 = k/2
1*2 = k
2 = k
So, when y is 6
x = 2/6
x = 1/3.
y = 80
12 years agoHelpfull: Yes(0) No(10)
1/9
1=k/4=>k=4
x=k/6^2
x=1/9
8 years agoHelpfull: Yes(0) No(1)

X varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to
A) 3 B) 9 C) 1/3 D) 1/9