The sum of the first 3 terms of a geometric series is 37/8. The sum of the first six terms is 3367/512. Find the ratio and first term

• S6 -S3=x
  x=3367/512-37/8
  x=999/512
  x=S3*R^3
  999/512=37/8 * R^3
  R^3=27/64
  R=3/4
  37/8=a(1-27/64)/1/4
  37/32=37a/64
  1184a=2368
  a=2
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