TCS
Company
3. A person is rock climbing at an altitude of 800 m. He go up by 7 mph, and come down by 9 mph. What was his average speed? a) 7.875mph b) 7.125 mph c) 7 mph d) 7.5 mph
Read Solution (Total 4)
-
- Average speed= 2xy/(x+y).
x=7,y=9
for confusing only he gives altitude. so
Average speed= 2*7*9/16=7.875
option a - 12 years agoHelpfull: Yes(5) No(0)
- a)7.875mph
Expln:
Let x and y be the speed of up and down.
Diff of speed(y-x) = 2mph
Avg speed = 2xy / x+y
= 2 *9*7 / (9+7) = 7.875 - 13 years agoHelpfull: Yes(3) No(0)
- His average speed is,
2*x*y/(x + y)
so,
2*7*9/(7 + 9) = 7.875 mph - 9 years agoHelpfull: Yes(2) No(0)
- by using the average speed, average speed = 2xy/(x+y)
so here, x=7 and y=9
average speed = 2*7*9/16=
7.875
so ans is option a - 8 years agoHelpfull: Yes(0) No(0)
TCS Other Question