A girl has to make pizza with different toppings. There are 8 different toppings. In how many ways can she make pizzas with 2 different toppings?
a) 16 b) 56 c) 112 d) 28

• it should be 8C2 ways which is (8*7)/(2*1) = 28 ways, because it is just a matter of selecting two of the toppings out of 8 toppings.
• 13 years agoHelpfull: Yes(26) No(2)
• b)56
  Expln: In 8 different toppings, selecting 2 diff toppings = 8c2
  formula is n!/(n-c)!
  n = total number of toppings
  C = number chosen in a grouping.
  n=8 and c=2 so we get
  8!/(8-2)! = (8*7*6*5*4*3*2*1)/(6*5*4*3*2*1)
  = 8*7 =56
• 12 years agoHelpfull: Yes(3) No(12)
• use formula=n!/(n-c)!
  here n=8 c=2
  substitute in above formulae we get answer to be 56
• 13 years agoHelpfull: Yes(2) No(7)
• There are 8C2 = 28 combinations for selecting 2 toppings each time.
  But considering the order of toppings on pizza, 28*2 = 56 combinations are possible.
• 12 years agoHelpfull: Yes(2) No(6)
• 8c2=8*7/2*1=28 ways
• 12 years agoHelpfull: Yes(2) No(0)