1. Simple question but big one on average age 5th like a, b, c weighted separately 1st a, b, c then a & b, then b & c, then c & a at last abc, the last weight was 167, then what will be the average weight of the 7 reading? a) 95 b) 95.428 c) 95.45 d) 94

• ans=b
  (a+b+c)+(a+b)+(b+c)+(c+a)+(a+b+c)/7=167
  add all the variable
  4(a+b+c)/7=167
  a+b+c/7=167*4
  =668/7
  95.428
• 12 years agoHelpfull: Yes(4) No(0)