Others Maths Puzzle

Let (10+x)/(110+x) = (20+y)/(120+y) = (30+z)/(130+z) = 1/n, where x, y, z and n are positive integers.

The number of distinct possible value of n is

(1) 2 (2) 4 (3) 3 (4) 1 (5) none of these

Read Solution (Total 3)

(1) 2

two values of n are possible .
when n=2, x=90, y=80, z= 70
when n=3, x=40, y=30, z=20
12 years agoHelpfull: Yes(2) No(0)

Ans.(1) 2
Values of x, y and z should be such that on simplifying fractions
(10+x)/(110+x), (20+y)/(120+y) and (30+z)/(130+z)we should get 1 in the numerator. For this possible values are
(x=90, y=80, z= 70) giving n = 2
and (x=40, y=30, z=20) giving n = 3
Thus number of distinct possible values of n are 2. Hence option (1) is correct
12 years agoHelpfull: Yes(1) No(2)
correct.
two values of n are possible .
12 years agoHelpfull: Yes(0) No(0)

Others Other Question

In a row of children facing north Kumar is fourth to the left of Anitha who is tenth from the left end. Vivek is second to the right of Anitha and eighth from the right end of the row. Total how many children are there in the row?

(1) 19

(2) 20

(3) 8

(4) 14

(5) None of these
An army 50 miles long marches at a constant rate. A courier standing at the rear moves forward and delivers the message to the first person and then turns back and reaches the rear of the army as the army completes 50 miles. Find the distance travelled by the courier.