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1) abcD+abcd+aBCd+aBCD
then the simplified function is
( Capital letters are copliments of corresponding letters A=compliment of a)
[a] a ab [c] abc [d] a(bc)* [e] none
(bc)*=compliment of bc
Read Solution (Total 3)
-
- abcD + abcd + aBCd + aBCD
= abc(D + d) + aBC(d + D)
= abc + aBC because d + D = 1 , D being complement of d
= a(bc + BC)
= a because bc + BC = 1, BC being complement of bc
- 13 years agoHelpfull: Yes(21) No(1)
- abcD+abcd+aBCd+aBCD
abc(D+d)+aBC(d+D)
abc(1)+aBC(1)
a(bc+BC)
a(1)=a
- 13 years agoHelpfull: Yes(7) No(3)
- abcD + abcd + aBCd + aBCD
= abc(D + d) + aBC(d + D)
= abc + aBC
= a (bc + BC)
= a (b XNOR c)
So, answer is option(e) none
- 13 years agoHelpfull: Yes(7) No(3)
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