CAT
Exam
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Out of 17 applicants 8 boys and 9 girls. Two persons are to be selected for the job. Find the probability that at least one of the selected persons will be a gir
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- 108/136=27/34=0.79
so probablity is 0.79 - 10 years agoHelpfull: Yes(3) No(0)
- Two persons are to be selected
so for girls=9c2= 36
so for boys=8c2=28
And for both= 17c2= 136
so condition is atleast there must be atleast 1 girl=Total-boys=136-28=108 - 10 years agoHelpfull: Yes(1) No(1)
- 9C2+9C1*8C1 =36+72=108
- 10 years agoHelpfull: Yes(1) No(2)
- answer is 0.79=(1-no girl is selected)=(1-(8C2/17C2))
- 10 years agoHelpfull: Yes(1) No(0)
- (9c1 * 8c1 + 9c2)/17c2
(72 + 36)/136
108/136
Ans. 0.794 - 10 years agoHelpfull: Yes(1) No(0)
- 8c0*9c2+8c1*9c1=
1*36+8*9+
36+72=108
- 10 years agoHelpfull: Yes(0) No(2)
- @Pradeep, bhagya, jaspal ....Probability lies between 0 to 1, then how 108?
- 10 years agoHelpfull: Yes(0) No(0)
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