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Maths Puzzle
Numerical Ability
Probability
1. What is the length of the longest rod that can be placed in a room 10m long, 6m broad and 4m high?
a. 7.21 m
b. 8.32 m
c. 10.91 m
d. 12.33 m
Read Solution (Total 3)
-
- ans.d
its along the diagonal of the cuboid.
length=10m, breadth=6m
length of diagonal of base rectangle=sqrt(10^2+6^2)=11.66
length of diagonal of cuboid= sqrt(4^2+11.66^2)=12.33m - 12 years agoHelpfull: Yes(7) No(5)
- the longest rod has length as the diagonal of the room.
so length of rod = sqrt(10^2 + 6^2 + 4^2)
= sqrt(152) = 12.33 approx. - 12 years agoHelpfull: Yes(6) No(4)
- (d) 12.33 m
the rod can be placed diagonally up resting on the wall.
diagonal length of the floor = sqrt(10^2+6^2) = sqrt(136)
len of diagonal from top corner to the bottom corner = sqrt(sqrt(136)^2 + 4^2)
= sqrt(136+16) = sqrt(152)
= 12.33 m
- 12 years agoHelpfull: Yes(1) No(4)
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