1. What is the length of the longest rod that can be placed in a room 10m long, 6m broad and 4m high?


a. 7.21 m
b. 8.32 m
c. 10.91 m
d. 12.33 m

• ans.d
  its along the diagonal of the cuboid.
  length=10m, breadth=6m
  length of diagonal of base rectangle=sqrt(10^2+6^2)=11.66
  length of diagonal of cuboid= sqrt(4^2+11.66^2)=12.33m
• 13 years agoHelpfull: Yes(7) No(5)
• the longest rod has length as the diagonal of the room.
  so length of rod = sqrt(10^2 + 6^2 + 4^2)
  = sqrt(152) = 12.33 approx.
• 13 years agoHelpfull: Yes(6) No(4)
• (d) 12.33 m
  the rod can be placed diagonally up resting on the wall.
  
  diagonal length of the floor = sqrt(10^2+6^2) = sqrt(136)
  
  len of diagonal from top corner to the bottom corner = sqrt(sqrt(136)^2 + 4^2)
  = sqrt(136+16) = sqrt(152)
  = 12.33 m
  
• 13 years agoHelpfull: Yes(1) No(4)