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Numerical Ability
Number System
‘a’ is greater than ‘b’ by 2 and ‘b’ is greater than ‘c’ by 10.
If a + b + c = 130, then (b +c) – a = ?
1) 38
2) 42
3) 44
4) 34
5) None of these
Read Solution (Total 7)
-
- ans: 34
a=b+2 ; b=c+10 hence a=c+12; a+b+c=130
solving this a=48 , b=46 , c=36
(b+c)=46+36=82-a=82-48=34 - 11 years agoHelpfull: Yes(23) No(0)
- The question is not clear. wat do you mean by ‘a’,‘b’,‘c’ and –? we can see only greek and latin here
- 12 years agoHelpfull: Yes(4) No(12)
- Here,
a=b+2
b=c+10
now put the above value in a+b+c=130 so,
a+b+c=130
b+2+b+b-10=130
3b-8=130
3b=138
so, b=46
a=48
c=36
now, (b+c)-a=(46+36)-48=34
so, Ans.:34 - 9 years agoHelpfull: Yes(3) No(0)
- ans-44
a=b+2
c=c+10
a+b+c=130
2+b+b+c=130
2b+c=128
2(c+10)+c=128
c=36
b=c+10
b=46
similarly,a=38
putting values,
b+c-a=44
- 10 years agoHelpfull: Yes(0) No(5)
- a+b+c=130
since, a>b by 2......then equation is : a-b=2......therefore,a=b+2
since, b>c by 10.........then equation is : b-c=10..........therefore, c=b-10
substitute the value of a and c in a+b+c=130
you will get b=46,then
substitute b in a=b+2,c=b-10
you will get values of: a=48,b=46,36
substitute them in (b+c)-a=you will get 34
- 9 years agoHelpfull: Yes(0) No(0)
- a+b+c=130
a=b+2
b=c+10
c=b-10
b+2+b+b-10=130
b=46
a=48
c=36
therefore (b+c)-1=34 - 5 years agoHelpfull: Yes(0) No(0)
- the answer is 34.
- 5 years agoHelpfull: Yes(0) No(0)
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