a,b,c are in continued proportion; b,c,d are also in continued proportion; if b:c = 2:3 and all
the four numbers are positive integers, what is the minimum possible value of (a+d)?

• a+d = 35
  
  a=8 and d=27
• 12 years agoHelpfull: Yes(2) No(0)
• Ans. Minimal possible value of (a+d) is 35
  
  Solution.
  a,b,c,d are in continued proportion, so
  a/b = b/c = c/d = 2/3
  => a = (2/3)*b , b = (2/3)*c , c = (2/3)*d
  => a = (2/3)*(2/3)*(2/3)*d = (8/27)*d
  => d = (27/8)*a
  As all the four numbers are positive integers, so
  minimal values of a = 8 giving d = 27
  Hence a + d = 35
• 12 years agoHelpfull: Yes(1) No(1)
• 35 is correct answer.
• 12 years agoHelpfull: Yes(0) No(0)