Let N = 2 × 5 × 8 × 11 × … × 2009

What is the number of zeroes at the end of the decimal representation of N?

OPTIONS
1)133
2)134
3)166
4)167
5)168

• There will be 167 zeroes at the end of the decimal representation of N.
• 12 years agoHelpfull: Yes(3) No(2)
• N = 2 × 5 × 8 × 11 × … × 2009
  
  If it is
  N = 2!* 5 !* 8!* 11 ! *...........2009 !
  
  then 167 seems correct.
• 12 years agoHelpfull: Yes(1) No(0)