2^(2x-1) = 1/(8^(x-3)), what is x?

• 2^(2x-1) = 1/(8^(x-3)),
  2^(2x-1) = 1/((2^3)^(x-3)),
  2^(2x-1) = 2^(9-3x)
  
  2x-1 = 9-3x
  5x=10
  x=2,
• 12 years agoHelpfull: Yes(4) No(0)
• 2^2x-1=1(/8^(x-3))
  2^2x/2=8^3/8^x
  4^x/2=2^9/8^x
  2^5x=2^10
  x=2
  
• 12 years agoHelpfull: Yes(1) No(1)
• 2^(2x-1)=1/8^(x-3))
  x?
  x=2
  
  
• 12 years agoHelpfull: Yes(0) No(2)
• 2^(2x-1)=1/(8^(x-3)
  2^(2x-1)=2^(-3x+9)
  2x-1=-3x+9
  5x=10
  x=2
• 12 years agoHelpfull: Yes(0) No(0)
• X=2
  
  2^(2x-1) = 1/(8^(x-3)) ..i.e 2^(2x-1) = 1/(2^(3x-9)),
  2^(2x-1) = (2^(-3x+9))
  2x-1 = -3x+9 ....Solving this X=2
  
  
  
• 12 years agoHelpfull: Yes(0) No(0)
• nice question
  2^(2x-1) = 1/(8^(x-3)),
  2^(2x-1) = (8^-(x-3),
  2^(2x-1) = (2^(3(x-3))),
  (2x-1) = 3(x-3),
  so x =2
  
• 12 years agoHelpfull: Yes(0) No(0)