Q. Solve
ALFA
+ BETA
+ GAMA
......
DELTA

Every alphabet has a numerical value to satisfy this equation.
Find values.

• 5795
  6435
  2505
  -----
  14735
• 12 years agoHelpfull: Yes(3) No(2)
• questions has mutiple answers.
  
  ALFA
  BETA
  GAMA
  ......
  DELTA
  
  When we are trying to add same number thrice, in result the first digit having the same number is possible with only 5. From So A can be 5 or Zero. In my example I have taken A as 5.
  After replacing A by 5 equation looks like
  5LF5
  + BET5
  + G5M5
  ....1.
  DELT5
  For Above we can conclude F+M+T+1 = T. In other words F+M+1=10.after furhter simplification F+M = 9
  Possible values are (0,9),(2,7),(1,8),(3,6),(4,5) and in reverse order as well
  In my Example I have taken F as 3 and M as 6 Equation becomes as
  5L35
  + BET5
  + G565
  ...11.
  DELT5 ....T can be any value from 0 to 9
  Now L+E+5+1=L. Means E+6 =0.. Further simplified as E=4, First Digit becomes Zero. Now Equation Becomes
  5L35
  + B4T5
  + G565
  ..111.
  D4LT5......L can be any value from 0 to 9
  Now 5+B+G+1 = D4. Assumed all the Alphabets are having numbers from 0 to 9
  B+G+6 = D4 Here D can be 1 or 2. I have Assumed D as 1
  Now equation becomes B+G = 8
  Possible B and G values are (2,6),(0,8),(1,7),(3,5),(4,4) and in reverse order also.
  
  All the above combinations still give you the correct result.
  
• 12 years agoHelpfull: Yes(3) No(5)
• Values of ALL those are,
  A=5 ; L=7; F=9; B=6; E=4; T=3; G=2; M=0; D=1;
  So that,
  ALFA = 5795 ; BETA = 6435; GAMA = 2505;
  
  Therefore, ALFA + BETA + GAMA = DELTA
  That is, 5795 + 6435 + 2505 = 14735 (which satisfy the conditions)
  
  Really nice question:->
• 12 years agoHelpfull: Yes(2) No(3)
• 5305
  2475
  6595
  ------
  14375
  
  
  
• 12 years agoHelpfull: Yes(2) No(0)
• @ Shiv,
  
  Pls check.
  
  B or G can not have value as 5 because A=5 is fixed ( by you also).
  B or G can not be zero or 4 .
  B and G can not have same value as 4.
  B or G can not be 1 as D can not have value other than 1.
  
  so B and G can have only value of 2 and 6 for which sol is already given by PPS , shikha and Vignesh.
  
  Pls check.
• 12 years agoHelpfull: Yes(1) No(1)
• There are multiple solutions....
  if every alphabet has a unique value then...
  A=5
  B=2 or 6
  E=4
  L=3 or 7 or 9
  T=3 or 7 or 9
  D=1
  G=2 or 6
  M=3 or 7 or 9
  these are all the possible solutions...
• 10 years agoHelpfull: Yes(1) No(0)
• here A=5,B=4,G=4,D=1,F=4,T=6,M=5,E=4,L=6
  so here is proof
  5645
  +4465
  +4555
  ........
  14665
• 12 years agoHelpfull: Yes(0) No(1)