A sum of money is borrowed and paid back in two annual instalments of Rs.882 each allowing 5% C.I.The sum borrowed was:      A. Rs.1680      B. Rs.1142      C. Rs.640      D. Rs.1640

• amount=p*(1+r/100)^n
  borrowed amount= 882 / (1+5/100) + 882 / (1+5/100)^2
  = (882*20)/21 + (882*20*20)/(21*21)
  = 1640
• 9 years agoHelpfull: Yes(20) No(6)
• Sum = 882 / 1.05 + 882 / (1.05^2)
  
  = Rs. 1640
• 9 years agoHelpfull: Yes(12) No(9)
• A = P(1+R/100)^1
  where A- amount P- Principal R- Rate of interest
  882 = p1(1 + 5/100)^1
  882 = P1(105/100)
  882 * (100/105) =P1
  p1 =840
  
  
  
  882 = P2(1 + 5/100)^2
  882 = P2(105/100)^2
  882 * 100/105 * 100/105 = P2
  P2 = 800
  
  p=p1+p2
  p=840+800
  ie. p=1640.
• 4 years agoHelpfull: Yes(6) No(0)
• yes 1640 is correct ans.
• 9 years agoHelpfull: Yes(4) No(5)
• sum=882/1.05+882/(1.05^2)
• 9 years agoHelpfull: Yes(2) No(6)
• c.i = p(1-r/100)^t
  here p=882,r=5,t=2
  then c.i = 797
  but sum = principle+interest
  sum=882+797 =1779.998=1788(apprx)
• 9 years agoHelpfull: Yes(1) No(18)
• 1680........................................................
• 9 years agoHelpfull: Yes(0) No(9)
• 5% CI is 42 per year.
  882 - 42=840 each year.
  so we add 840 + 840 = 1680 is the correct answer..........................
• 7 years agoHelpfull: Yes(0) No(3)
• Sum = 882 / 1.05 + 882 / (1.05^2)
  ans: 1640
• 4 years agoHelpfull: Yes(0) No(0)